/*
 	COMP 2401/2001 W13

	You have to know what is happening with arrays.  Some basic opertors
	do not behave as you might initially expect them to.

	Arrays cannot be "copied" with the "=" assignment operator
	like primitive types can.

	Using "==" equality operator only checks for pointer equality.
	It does not check if the contents of two arrays are the same or not.

	Using one of the relational operators <, <=, >, >= will
	check pointer values.  You can use these but they have nothing to
	do with the data in the array.  They check if one pointer is located
	in memory before or after another.

   mjh 2013
*/

#include <stdio.h>

int main(){
	int a[] = {1,2,3,4,5};
	int b[] = {1,2,3,4,5};
	int *c = a;

/* uncomment this code and see the error 

	//int d[5] ;
	//d = a;      // annot copy an array with "=" operator

*/


	printf("(a == b) is ");
	if( a==b ) printf("true\n");
	else printf("false\n");

	printf("(a == c) is ");
	if( a==c ) printf("true\n");
	else printf("false\n");

	printf("(b == c) is ");
	if( b==c ) printf("true\n");
	else printf("false\n");

	


}