/*
	COMP2401/2001 - W13

	Be careful when initializing arrays of chars (strings)

	Remember:
		Every string is an array of chars (which is just a pointer to a char).
		But, every char* (array of chars) is not a string.

		Strings are arrays of chars that end with the '\0' NULL character.

	mjh - 2013
*/


/*
	run the code with the local comments in place and also commented out.  
	Make sure you know why there is a difference in the output.
*/



#include <stdio.h>

	// this initialization does NOT automatically add a '\0' to the
	// end of the array
	char b[] = {'t', 'w', 'o', ' ', 'f', 'i', 's', 'h'};

	// this initialization DOES automatically add the '\0' to the end
	char a[] = "one fish";


   char c[5] = "abc";




int main(){
	// initializing an array with at least 1 less char than the array
	// was created for will automatically fill the remaining chars with
	// zeros.  (and zero is ASCII value for '\0', which is NULL)
	const int size = 100;
	char b[size+1] = {'t', 'w', 'o', ' ', 'f', 'i', 's', 'h'};


	char a[] = "one fish";
   char c[5] = "abc";


	printf("string a = \"%s\"\n", a);
	printf("string b = \"%s\"\n", b);


}